(3/4)^x-3=(16/9)^1+2x

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Solution for (3/4)^x-3=(16/9)^1+2x equation: 



(3/4)^x-3=(16/9)^1+2x

We move all terms to the left:

(3/4)^x-3-((16/9)^1+2x)=0



Domain of the equation: 4)^x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 9)^1+2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)^x-((+16/9)^1+2x)-3=0

We calculate fractions


2x+27^1)/4^x*9)^1+2x))+(-64^x/4^x*9)^1+2x))-3=0

We can not solve this equation

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